Question

find the area of the triangle whose side are 48cm,73cm ,55cm​

Answer 1

Answer:

Step-by-step explanation:

I used Heron's formula that states that the area of a triangle can be represented as a $\sqrt{s(s-a) (s-b) (s-c)$  where s is the semi perimeter of the triangle and a, b and c are the side lengths of the triangle.

The semi perimeter of the given triangle is : s = (48+73+55) / 2 =   88 cm

thus by Herons formula the area of the triangle is :

$\sqrt{88( 88-48) (88-73) (88-55)}$  = 1320 $cm^{2}$