Question

find the area of the triangle whose sides are 13 cm 20 cm and 21 CM also find the altitude of the triangle corresponding to the largest side

Answer 1

this is your solution

Answer 2

S=a+b+c/2
=13+20+21/2
=27
area=√s(s-a)(s-b)(s-c)
√27×(27-20)(27-13)(27-21)
√27×7×14×6
=126cm²
area =1/2×21×h=126
h=(126×2)/21
h=12cm