find the area of the triangle whose sides are 30 cm 24cm 18cm also find the length of the altitude corresponding to the smallest side of the triangle
Answers
we can find the altitude with yhe help of heron's formula
here s = 24 + 18 + 30/2
72/2
=36
s=36
under square root s*(s-a)(s-b)(s-c)
under square root 36*6*12*18
answer is 216.
216 is our area of triangle
now we can easily find the height
216 = 1/2*base*height
216 = 1/2*18*h
216*2/18 = h
h = 24 cm
Solution :-
Given : Suppose that, Side a = 30 cm, Side b = 24 cm, Side c = 18 cm
Semi perimeter = (a + b + c)/2
= (30 + 24 + 18)/2
= 72/2 = 36 cm
By heron's formula,
Area of triangle = √{s(s - a) (s - b) (s - c)}
= √{36×(36−30)×(36−24)×(36−18)}
= √{36×6×12×18}
= √{216×12×18}
= √46656
= 216
Find the length of the altitude corresponding to the smallest side of the triangle :
Height = 2 × (Area of triangle)/(Base)
= 2 × (216)/18 cm
= 432/18 cm
= 24 cm
Hence,
Area of triangle = 216 cm²
Height = 24 cm