Find the area of the triangle whose sides are 42 cm, 34 cm, and 20 cm in length . hence , find the height corresponding to the longest side.
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Here, a=42cm, b=34cm, c=20cm
Area= root over (s x (s-a) x (s-b) x (s-c)) where s is semi perimeter i.e perimeter/2
=root over(48 x 6 x14 x 28)=336 sq.cm
Area is also equal to (1/2)bcsinA =(1/2)(34)(20)(h/a)
draw a diagram to understand
(17)(20)(h/42)=336
h=41.37cm
Area= root over (s x (s-a) x (s-b) x (s-c)) where s is semi perimeter i.e perimeter/2
=root over(48 x 6 x14 x 28)=336 sq.cm
Area is also equal to (1/2)bcsinA =(1/2)(34)(20)(h/a)
draw a diagram to understand
(17)(20)(h/42)=336
h=41.37cm
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