Find the area of the triangle whose sides are 42 cm 34cm 20cm in lenth.Hence ,find the height corresponding to the longest side. Hurry up
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Perimeter = Sum of all sides
Semiperimeter (s) = (42 + 34 + 20 ) / 2
So it is = 96 / 2 = 48 cm.
Using herons formula = (√s )(√s-a )(√s-b) (√s-c)
By substituting s and a , b , c i.e the given sides.
We have √48 × √6 × √14 × √28
So √ (4 × 6 × 2) × √6 × √(7 × 2) × √(7 × 4)
Simplifying the numbers we have area = 4 × 6 × 2 × 7 = 336 cm ²
Hence area is 336 cm²
Now height corresponding to longest side implies that base is 42 cm and area remains same
So area of triangle is 1/ 2 b × h
336 = 1/ 2 × 42 × H
then , height =( 336 *2 )/42
= 672 / 42 = 16 cm is the longest side.
Semiperimeter (s) = (42 + 34 + 20 ) / 2
So it is = 96 / 2 = 48 cm.
Using herons formula = (√s )(√s-a )(√s-b) (√s-c)
By substituting s and a , b , c i.e the given sides.
We have √48 × √6 × √14 × √28
So √ (4 × 6 × 2) × √6 × √(7 × 2) × √(7 × 4)
Simplifying the numbers we have area = 4 × 6 × 2 × 7 = 336 cm ²
Hence area is 336 cm²
Now height corresponding to longest side implies that base is 42 cm and area remains same
So area of triangle is 1/ 2 b × h
336 = 1/ 2 × 42 × H
then , height =( 336 *2 )/42
= 672 / 42 = 16 cm is the longest side.
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