Find the area of the triangle whose sides are 42 cm, 34cm and 20 cm in Lengthe Hence find the height corresponding to the longest side
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19.76 cm hope it will help you
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Answer:
A =√{s(s-a)(s-b)(s-c)}
s=(42+34+20)/2=48
A=√{48×(48-42)(48-34)(48-20)}
=√(48×6×14×28)
=6×7×8=336
height:=h
(1/2)×42×h=336
h=336×2/42=16
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