Question

find the area of the triangle whose sides are 42 cm ,34cm,and 20 cm in length. Hence, find the height corresponding to the to the longest side.

Answer 1

heya mate here is your answer.......

Answer 2

here height of triangle is equal to
$= \sqrt{ {20}^{2} + {21}^{2} } \\ = \sqrt{400 + 441} \\ \ = \sqrt{841 } \\ = 29$
area of triangle =1/2hb
=1/2×29×42
=609