Question

Find the area of the triangle whose sides are 50 cm, 48 cm and 14 cm. Find the height of thetriangle corresponding to the side measuring 48 cm.

Answer 1

Heya, ______________________________

$s = \frac{50 + 48 + 14}{2} \\ = \frac{112}{2} = 56 \\ \sqrt {56(56 - 50)(56 - 48)(56 - 14)} \\ = \sqrt{56 \times 6 \times 8 \times 42} \\ = \sqrt{2 \times 2 \times 2 \times 7 \times 6 \times 2 \times 2 \times 2 \times 7 \times 6} \\ = 2 \times 2 \times 2 \times 7 \times 6 \\ = 336 {cm}^{2}$

Area = 1/2 × base × height

336cm^2 = 1/2 × 48 cm× h

336 cm^2 × 2/48 = h

14 cm = height

Hooe it helps☺!

Answer 2

Dear Student,

◆ Answer -

A = 336 cm^2

h = 14 cm

● Explanation -

# Given -

a = 50 cm

b = 48 cm

c = 14 cm

# Solution -

Semiperimeter is given by -

s = (a+b+c)/2

s = (50+48+14)/2

s = 56 cm

Area of triangle is -

A = √[s(s-a)(s-b)(s-c)]

A = √[56(56-50)(56-48)(56-14)]

A = √(56 × 6 × 8 × 42)

A = √(112896)

A = 336 cm^2

Let h be height of the triangle is -

A = 1/2 × b × h

336 = 1/2 × 48 × h

h = 336 / 24

h = 14 cm

Hence, area of triangle is 336 cm^2 and height of the triangle corresponding to 48 cm side is 14 cm.

Thanks dear...