Question

Find the area of the triangle whose sides are 7.5cm, 18cm,19.5cm​

Answer 1

Answer:

67.5 sq.cm

Step-by-step explanation:

Area of triangle = $\sqrt{s(s-a)(s-b)(s-c)}$

Here 's' = Perimeter/2 = 7.5 + 18+ 19.5 / 2 = 45/2 = 22.5

$\sqrt{22.5(22.5 - 7.5)(22.5 - 18)(22.5 - 19.5)}$

= $\sqrt{22.5(15)(4.5)(3) }$

= $\sqrt{4556.25}$

= 67.5 sq.cm

Hence the area of the triangle is 67.5 sq.cm