Question

find the area of the triangle whose sides are 80cm,82cm and 18cm

Answer 1

Answer:

720 cm square

Step-by-step explanation:

Area of triangle=1/2×base×height

=1/2 × 18cm × 80cm

=720 cm square

Answer 2

Given:-

• Sides of Triangle ABC

• AB = 80cm
• BC = 82cm
• CA = 18cm

To find:-

• Area of Triangle ABC

Solution:-

Using Heron's Formula:-

Firstly we have to find semi - perimeter (s),

$:\implies\sf s = \dfrac{a + b + c}{2}$

$:\implies\sf s = \dfrac{80 + 82 + 18}{2}$

$:\implies\sf s = \cancel{ \dfrac{180}{2}}$

$:\implies\sf s = 90$

$\rule{200}3$

Now, put value in formula:-

$:\implies\sf A = \sqrt{s(s - a) + s(s - b) + s(s - c)}$

$:\implies\sf A = \sqrt{90(90 - 80)(90 - 82)(90 - 18)}$

$:\implies\sf A = \sqrt{90 \times 10 \times 8 \times 72}$

$:\implies\sf A = \sqrt{518400}$

$:\implies\sf A = \bf{720\;cm^2}$

$\rule{200}3$