Find the area of the triangle whose sides are along the lines x=2,y=0,and 4x+5y=20.
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Answer:
Given the equation of the straight line is 4x+5y=20 can be written as
5
x
+
4
y
=1.
From this it is clear that the x− and y− intercepts are 5 and 4 units respectively.
So the area of the triangle formed by the x−, y− and the given line is
=
2
1
×4×5
=10 sq. units.
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