Find the area of the triangle whose sides are in ratio 5:12:13 and it's perimeter is 6 centimetre
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5x+12x+13x=6
then
x= 1/5
then
1st side = 1
2nd side = 12/5
3rd side = 13/5
but 5:12:13 is the triplet the traingle must be right angled then
base = 1
height = 12/5
area = 1x1x12/2x5
area = 12/10
area = 6/5centimetre square
then
x= 1/5
then
1st side = 1
2nd side = 12/5
3rd side = 13/5
but 5:12:13 is the triplet the traingle must be right angled then
base = 1
height = 12/5
area = 1x1x12/2x5
area = 12/10
area = 6/5centimetre square
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