Question

find the area of the triangle whose sides are of length 8 CM 11 cm and 13 cm ​

Answer 1

Perimeter of triangle = sum of all sides

= 8+11+13

=32

Then find s

S= p/2

= 32/ 2

= 16

By herons formulaula

√ s( s- a) ( s- b) s- c) where a,b and c are the sides of triangle

= 16 (16-8)(16-11)(16-13)

=√ 16 × 8×5× 3

=√ 128× 5×3

=√ 640× 3

=√ 1920