Question

find the area of the triangle whose vertices are (0,0), (a,0) and (0,b)

Answer 1

Answer:

Area of triangle = 1/2[x1(y2-y3)+x2[y3-y1]+x3(y1-y2)]

A(0,0) B(a,0) and C(0,b)

=1/2[0(0-b)+a(b-0)+0(0-0)

=1/2[0+ab+0]

=1/2(ab)

=ab/2

HOPE THIS ANSWER WILL HELP YOU

Answer 2

Answer:

points are collinear....area is 0