Question

Find the area of the triangle whose vertices are (1,0),(6,0)and(4,3)
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Answer 1

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Answer 2

Step-by-step explanation:

Given that:Find the area of the triangle whose vertices are (1,0),(6,0)and(4,3)

Solution: Area of triangle when three vertices A(x1,y1),B(x2,y2) and C(x3,y3) are given

$\bold{Area\:of\: triangle=\frac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|}$

A(1,0),B(6,0) and C(4,3)

Put value of A,B and C

$Area\:of\: triangle=\frac{1}{2}|1(0-3)+6(3-0)+4(0-0)\\\\=\frac{1}{2}|-3+18+0|\\\\=\frac{1}{2}|15|\\\\=7.5\:unit^2$

Area of triangle with given vertices is 7.5 sq-unit.

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