Question

Find the area of the triangle whose vertices are (1,-1),(-4,6) and (-3,-5)

Answer 1

area of triangle is -

$\frac{1}{2} ( \: \: 1(6 + 5) - 4( - 5 + 1) - 3( - 1 - 6) \: \: )$
$\frac{1}{2} (11 + 16 + 21)$
$\frac{1}{2} \times 48$
$24$
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Answer 2

This question has already been answered by @MaheswariS at https://brainly.in/question/1423056.

Answer:

Area of the triangle formed by given 3 points is 24 square units

Explanation:

Formula used:

Area of the triangle formed by the points

$(x_1, y_1),\; (x_2, y_2) \:and \:(x_3, y_3)\:is\\\\|\frac{1}{2}[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|\:\:square\:units$

Given points are (1, -1), (-4, 6)and (-3, -5)

Area of the triangle

$=|\frac{1}{2}[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|\:\:square\:units\\\\=|\frac{1}{2}[1(6+5)-4(-5+1)-3(-1-6)|\\\\=|\frac{1}{2}[1(11)-4(-4)-3(-7)|\\\\=|\frac{1}{2}[11+16+21]|\\\\=|\frac{1}{2}[48]|\\\\=24\:square\:units$