find the area of the triangle whose vertices are (1,2),(2,3),(5,7)
Answers
Answered by
1
Answer:
2
+
5
3
=
4
Solve
1
Subtract
5
3
\frac{5}{3}
35
from both sides of the equation
2
+
5
3
=
4
2
+
5
3
−
5
3
=
4
−
5
3
2
Simplify
Subtract the numbers
Subtract the numbers
2
=
7
3
3
Divide both sides of the equation by the same term
2
=
7
3
2
2
=
7
3
2
4
Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
=
7
6
Solution
=
7
6
Similar questions