Question

find the area of the triangle whose vertices are (2,1) , (1,4) , (-3,2)​

Answer 1

Answer:

7 sq.units

Step-by-step explanation:

Vertices are A(2,1), B(1,4), C(-3,2)

x₁ = 2, y₁ = 1, x₂ = 1, y₂ = 4, x₃ = 3, y₃ = 2

Putting values,

area of triangle ABC = (1/2)[x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)]

=> (1/2)[2(4 - 2) + (2 - 1) + -3(1 - 4)]

=> (1/2)[2(2) + 1 + -3(-3)]

=> (1/2)[4 + 1 + 9]

=> 14/2

=> 7 sq.units

Hence, Area of triangle = 7 sq.units.

#Hope my answer helped you!