Question

find the area of the triangle whose vertices are (-2 ,1), (3, 1) (2, -3)​

Answer 1

Answer:

ans triangle area=10 sq.units

Step-by-step explanation:

formula

1/2[(x1y2+x2y3+x3y1)-(x2y1+x3y2+x1y3)]

(x1,y1)=(-2,1) (x2,y2)=(3,1), (x3,y3)=(2,-3)

1/2[(-2-9+2)-(6+2+3)]

1/2[-9-11]=1/2(-20)=-10

10 sq.units