Question

Find the area of the triangle whose vertices are (-2,1), (3,1) ,(2,-3)

Answer 1

Answer:

1/2(-2(1+3)3(-3-1)2(1-1)

1/2(-2×4+3×-4+2×0)

1/2(-8-12+0)

1/2×-20

=-10

since area cannot be negative so area is 10

Answer 2

A(-2,1) B(3,1) C(2,-3)

X1 = -2         X2 = 3       X3 = 2

Y1 = 1         Y2 = 1       Y3 = -3

= 1/2  {x1(y2-y3) + x2(y3-y1) + x3(y1-y2)}

= 1/2 {-2 (1-(-3)) + 3 (-3-1) + 2(1-1)}

= 1/2 {-8-12+0}

= 1/2 {-20}

= 1/2 * -20

= -10

area of triangl is 10 because it can't be negative.

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