Math, asked by kajalpr96711, 1 year ago

find the area of the triangle whose vertices are (2,-2) ,(4,3) , (1,2) using integration

Answers

Answered by Anonymous
2

Area=1/2{2(3-2)+4(2+2)+1(-2-3)}

1/2(2+16-5)

1/2*13

13/2=6.5 sq units

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