find the area of the triangle whose vertices are (2,3) (-1,0) (2,-4)
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Answer:
the area will be 2, 6 3 e e
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vertices are-
X1= 2. X2=-1. X3=2
Y1=3. Y2= 0 Y3=-4
Area Of Rectangle=
1/2[X1(Y2-Y3)+X2(Y3-Y1)+X3(Y1-Y2)]
=1/2[2(0+4)-1(-4-3)+2(3-0)]
=1/2[2×4-1×-7+2×3]
=1/2[8+7+6]
=1/2×21
=10•5 squareunit
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