Math, asked by odyuowonchilo, 9 months ago

find the area of the triangle whose vertices are(2,3),(-1, 0),(2,-4)​

Answers

Answered by umasaini1816
3

Answer:

area of Δ = 1/2× { x1 (y2-y3) + x2(y3-y1) + x3(y1-y2) }

               = 1/2 ×{ 2 (0- (-4) ) + (-1) ( -4 - 3 ) + 2 (3- 0 )}

               =1/2 ×{ 8 + 7 + 6 }

               = 1/2 × 21

area of Δ= 10.5

Answered by DevillHeart
7

Answer:

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