find the area of the triangle whose vertices are (2,3) (3,-5) (4,-2)
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Answer:
Area of a triangle may be 11/2 or 5.5
Step-by-step explanation:
delta = 1/2 | X1 [Y2- Y3] + X2 [Y3-Y1] + X3 [Y1-Y2]|
= 1/2 | 2 [-5 -(-2) ] + 3 [-2-3] + 4 [3-(-5)] |
= 1/2 | 2 [-5+2] + 3 [ -5] + 4 [8] |
=1/2 | 2 [-3] + [-15] + 32 |
= 1/2 | -6 -15 + 32 |
=1/2 | -21 +32 |
=1/2 |11|
= 11/2 OR 10.5
MAY BE IT IS HELPFUL
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