Question

Find the area of the triangle whose vertices are (3, 1), (–1, 3) and (–3, –2).

Answer 1

Answer:

12 sq. units

Step-by-step explanation:

Area of a triangle = $\frac{1}{2}$ [ $x_{1} (y_{2} - y_{3}) + x_{2} (y_{3} - y_{1}) + x_{3} (y_{1} - y_{2} )$ ]

⇒ $\frac{1}{2}$ [ 3 (3+2) + (-1) (-2 -1) + (-3) (1 - 3) ]

⇒ $\frac{1}{2}$ [15 + 3 + 6]

⇒ $\frac{1}{2}$ [24]

⇒ 12 sq. units

Thanks,

Manav

Answer 2

Answer:

Step-by-step explanation: