Math, asked by sivanvimal1, 1 month ago

)Find the area of the triangle whose vertices are (3,-7),(-3,3)and (7,9).​

Answers

Answered by vaibhavsmartkid
0

Answer:

Step-by-step explanation:

Given: (3, -7), (7, 9), (-3, 3)

Let us Assume A(x1, y1) = (3, -7)

Let us Assume B(x2, y2) = (7, 9)

Let us Assume C(x3, y3) =(-3, 3)

= 1/2×|X1(Y2-Y3)+X2(Y3-Y1)+X3(Y1-Y2)|

= 1/2×|3(9-3)+7(3-(-7))+(-3)(-7-9)|

= 1/2×|3(6)+(3×7)-(-3x(-16)|

= 1/2×|18-21-48|

= 1/2×|-51|

= -25.5 unit.sq

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