Question

find the area of the triangle whose vertices are( 3,8) (- 4,2 )and( 5 ,- 1)?​

Answer 1

Answer:

Step-by-step explanation:

Mark three points A,B,C in the triangle:

A(3,8),(x1,y1),

B(-4,2),(x2,y2),

C(5,-1),(x3,y3),

So,Area of triangle is 1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)],

1/2[3{2-(-1)}+-4{-1-(+8)}+5{8-2}],

1/2[3(2+1)+-4(-1-8)+5(6)],

1/2[3(3)-4(-9)+5(6)],

1/2[9+36+30],

1/2[75],

37.5 square.units.

So,area of the traingle is 37.5 square units.

And sorry for no diagram.

Hope it helps you.