Find the area of the triangle whose vertices are (4,3) , (1,4) , (2,3)
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Answer:
1 sq unit
Step-by-step explanation:
area of triangle=1/2|X1(y2-y3)+X2(y3-y1)+X3(y1-y2)|
area=1/2|4(4-3)+1(3-3)+2(3-4)|
=1/2|4(1)+1(0)+2(-1)|
=1/2|4+0-2|
=1/2|2|
=1 squnit
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