Question

find the area of the triangle whose vertices are (5,2), (3,-5), (-5,-1) ​

Answer 1

$Area=|\frac{1}{2}[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]|\\\\Area =|\frac{1}{2}[5(-5-(-1))+3(-1-2)+(-5)(2-(-5)]|\\\\Area=|\frac{1}{2}(5(-5+1)+3(-3)-5(2+5)]|\\\\Area =|\frac{1}{2}[5(-4)-9-5(7)]|\\\\Area =|\frac{1}{2}[-20-9-35]|\\\\Area =|\frac{1}{2}[-29-35]|\\\\Area =|\frac{1}{2}[-64]|\\\\Area =|-32|\\\\Area =32units$

Answer 2

Answer:

Step-by-step explanation: