Question

find the area of the triangle whose vertices are:(5,_7),(-4,_5),(4,5)​

Answer 1

Answer:

1/2|5(-5-5)+-4(5+7)+4(-7+5)|=

1/2|5(-10)-4(12)+4(-2)|=

1/2|-50-48-8|=

106/2=

53

Answer 2

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Coordinates of vertices of triangle ABC is given by:

A(x1,y1)≡(−5,7),B(x2,y2)≡(4,5) and C(x3,y3)≡(−4,−5)

Area of triangle in coordinate system is given by:

=21[(x1−x3)(y1−y2)−(x1−x2)(y2−y3)]

= 2(−5−(−4))(7−5)−(−5−4)(5−(−5))

= 44 sq. units