Question

Find the area of the triangle whose vertices are (6,-6) (3,-7) (3,3)

Answer 1

Answer:

15 sq. units

Step-by-step explanation:

A(6,-6)⇔(x₁,y₁)

B(3,-7)⇔(x₂,y₂)

C(3,3)⇔(x₃,y₃)

ar(ΔABC)=¹/₂[x₁(y₂-y₃)+x₂(y₃-y₁)+x₃(y₁-y₂)]

ar(ΔABC)=¹/₂[6(-7-3)+3(3+6)+3(-6+7)]

ar(ΔABC)=¹/₂[-60+27+3]

ar(ΔABC)=¹/₂[-30]

ar(ΔABC)=-15 sq. units

As area cannot be negative area of ΔABC is 15 sq. units.

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