Question

find the area of the triangle whose vertices are A(1, 1) B(4, 4) C(4, 8)​

Answer 1

Option number is

B) (4,4)

hope it helps

Answer 2

Answer:

A=(1,1,1),B=(1,2,3),C=(2,3,3)

a = length of AB=(1−1)2+(2−1)2+(3−1)2=5

b= length of BC=(2−1)2+(3−2)2+(3−3)2=2

c= length of AC=(2−1)2+(3−1)2+(3−1)2=3

Semi-perimeter s=2a+b+c=23+2+5

Area of ΔABC=s(s−a)(s−b)(s−c)

=(23+2+5