Question

Find the area of the triangle whose vertices are A(1 2) B(-2 3) and C(-3 -4) (a) 11 sq.units (b) 22 sq.units (c) 7 sq.units (d) 6.5 sq.units​

Answer 1

Answer:

11 units

Step-by-step explanation:

Hope this is helpful to you !

Answer 2

Step-by-step explanation:

Plot the points in a rough diagram and take them in order.

Let the vertices be A(1,2),B(−3,4) and C(−5,−6)

Now the area of △ABC is

=½{ ( x1y2 + x2y3 + x3y1) − (x2y1 + x3y2 + x1y3 )}

= ½ {(4+18−10)−(−6−20−6)}

= ½ (12+32)

=22 sq.units.