Math, asked by hardikvikash123, 11 hours ago

find the area of the triangle whose vertices are a(-10 -6) (-8-1) and (-3-5)


please​

Answers

Answered by oes349a
0

Answer:

24.5

Step-by-step explanation:

(10,−6);(2,5);(−1,3)

x

1

y

1

x

2

y

2

x

3

y

3

=Area=

2

1

∣x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

1

−y

2

)∣

=

2

1

∣10(5−3)+2(3+6)−1(−6−5)∣

=

2

1

∣10(2)+2(9)−1(−11)∣

=

2

1

∣20+18+11∣

=

2

1

∣49∣

=24.5

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