find the area of the triangle whose vertices are a(-10 -6) (-8-1) and (-3-5)
please
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Answer:
24.5
Step-by-step explanation:
(10,−6);(2,5);(−1,3)
x
1
y
1
x
2
y
2
x
3
y
3
=Area=
2
1
∣x
1
(y
2
−y
3
)+x
2
(y
3
−y
1
)+x
3
(y
1
−y
2
)∣
=
2
1
∣10(5−3)+2(3+6)−1(−6−5)∣
=
2
1
∣10(2)+2(9)−1(−11)∣
=
2
1
∣20+18+11∣
=
2
1
∣49∣
=24.5
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