Math, asked by aarthisivanthirajan, 7 months ago

Find the area of the triangle whose vertices are A(2,4), B(-3,7) and C(-4,5)​

Answers

Answered by Banerjeejayasree
1

Answer:

Step-by-step explanation:

Plot the points in a rough diagram and take them in order.

Let the vertices be A(1,2),B(−3,4) and C(−5,−6)

Now the area of △ABC is

=  

2

1

​  

{(x  

1

​  

y  

2

​  

+x  

2

​  

y  

3

​  

+x  

3

​  

y  

1

​  

)−(x  

2

​  

y  

1

​  

+x  

3

​  

y  

2

​  

+x  

1

​  

y  

3

​  

)}

=  

2

1

​  

{(4+18−10)−(−6−20−6)}

=  

2

1

​  

(12+32)=22 sq.units.

Answered by Thejasks714
0
Answer would be 53sq. units.

Hope it helped pls mark as brainiest and thank
Similar questions