find the area of the triangle whose vertices are a ( 2,6) (7,8) (1,1)
Answers
As We know that the vertices of the triangle are (2,6) (7,8) (1,1).
- (2,6) = (x₁ , y₁)
- (7,8) = (x₂ , y₂)
- (1,1) = (x₃ , y₃)
We can find the area of the triangle using ½[x₁(y₂-y₃) + x₂(y₃-y₁) + x₃(y₁-y₂)] Formula.
→ ½[x₁(y₂-y₃) + x₂(y₃-y₁) + x₃(y₁-y₂)]
→ ½[2(8-1) + 7(1-6) + 1(6-8)]
→ ½[2(7) + 7(-5) + 1(-2)]
→ ½[14 -35 - 2]
→ ½[-23]
→ -23/2
Hence,
The area of the triangle is –23/2 using the following vertices.
Answer:
As We know that the vertices of the triangle are (2,6) (7,8) (1,1).
(2,6) = (x₁ , y₁)
(7,8) = (x₂ , y₂)
(1,1) = (x₃ , y₃)
We can find the area of the triangle using ½[x₁(y₂-y₃) + x₂(y₃-y₁) + x₃(y₁-y₂)] Formula.
→ ½[x₁(y₂-y₃) + x₂(y₃-y₁) + x₃(y₁-y₂)]
→ ½[2(8-1) + 7(1-6) + 1(6-8)]
→ ½[2(7) + 7(-5) + 1(-2)]
→ ½[14 -35 - 2]
→ ½[-23]
→ -23/2
Hence,
The area of the triangle is –23/2 using the following vertices.