Question

Find the area of the triangle whose vertices are (acidα,bsinα),(acosβ,bsinβ),(acos¥,bsin¥)

Answer 1

[acosA    bsinA    1]  =abcosA{sinB-sinY}-absinA{cosB-cosY}+ab{cosBsinY-sinB
[acosB    bsinB    1]       cosY}
[acosY    bsinY    1]    =ab{sin(B-A)+sin(A-Y)+sin(Y-B)}