Math, asked by jayaarora, 7 months ago

find the area of the triangle whose vertices are (at1,a/t1),(at2,a/t2),(at3,a/t3)

Answers

Answered by asha202
6

Answer:

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Step-by-step explanation:

Find the area of triangle if vertices are a b C (at1,a/t1) (at2,a/t2) (at3,a/t3) Use the formula: A=(1/2) [x1(y2-y3) +x2(y3-y1) +x3(y1-y2)]. In this case, A=(1/2) [at1(a/t2-a/t3)+ at2(a/t3-a/t1)+ at3 (a/t1-a/t2)] =(a²/2) [(t1-t2) (t2-t3)(t3-t1)/(t t2 t3)].

Answered by rajendra7388956838
0

Step-by-step explanation:

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