Question

Find the area of the triangle whose vertices are:

i] (4,5);(0,7);(-1,1) *​

Answer 1

Step-by-step explanation:

s=1/2[4×6+0+(-1)(-2)=1/2[24+2]=1/2×26=13 therefore,the area of the triangle is 13 square unit

Answer 2

Given:-

• Vertices of the Triangle are (4,5);(0,7);(-1,1).

To Find:-

• Area of the Triangle.

SoluTion:-

Let, The Traingle be ABC

Vertex A = (4,5) → $\sf{(x_1,y_1)}$

Vertex B = (0,7) → $\sf{(x_2,,y_2)}$

Vertex C = (-1,1) → $\sf{(x_3,y_3)}$

WKT

$\boxed{\star{\boxed{\tt{Area\;of\; Triangle = \frac{1}{2}|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)|sq. units}}}}$

$→\;{\sf{\frac{1}{2}|4(7-1)+0(1-5)+(-1)(5-7)|}}$

$→\;{\sf{\frac{1}{2}|4(6)+0+(-1)(-2)|}}$

$→\;{\sf{\frac{1}{2}|24+2|}}$

$→\;{\sf{\frac{1}{2}|26|}}$

$→\;{\sf{\frac{1}{2}±26}}$

$→\;{\sf{±13\;sq. units}}$

.:. Area of ∆le ◕➜ $\Large{\red{\mathfrak{13\;sq.units}}}$

Hope It Helps You ✌️