Question

Find the area of the triangle whose vertices have co-ordinates:

(6, 2), (- 3, 4), (4, - 3)​

Answer 1

Step-by-step explanation:

A(6, 2) , B(- 3, 4) , C (4, - 3)

AB=√(x2-x1)²+(y2-y1)²

=√[6-(-3)]²+(2-4)²

=√(6+3)²+(-2)²

=√9²+4

=√81+4

=√85

BC=√(x2-x1)²+(y2-y1)²

=√(-3-4)²+(4-(-3)²

=√(-7)²+(4+3)²

=√49+49

=√98

=√2×49

=7√2

AC=√(x2-x1)²+(y2-y1)²

=√(6-4)²+(2-(-3)²

=√2²+5²

=√4+25

=√29