Question

Find the area of the triangle with base ( 2a-b ) and its corresponding height 1/2b^2+3 .

Plz aaltu faltu ka answer nhi bhejna

Answer 1

Area of triangle =1/2 x base x height
= 1/2 x (2a -b) x 1/2 b^2+3
=1/4 x (2a -b) (b^2+3)
=1/4 x 2ab^2 +6a -b3 - 3b

Hence area of triangle is
1/4 x {(-b^3 +2ab^2 +6a -3b)}

Answer 2

Answer:Area of triangle =1/2 x base x height

= 1/2 x (2a -b) x 1/2 b^2+3

=1/4 x (2a -b) (b^2+3)

=1/4 x 2ab^2 +6a -b3 - 3b

Hence area of triangle is

1/4 x {(-b^3 +2ab^2 +6a -3b)}