Find the area of the triangle with perimeter 22 cm one side 9 cm and difference of other two sides is 7 ccm
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Answered by
0
area= 1/2*b*h
so b=9
h=7
=>1/2*9*7
=63/2
=32.5cmpower2
so b=9
h=7
=>1/2*9*7
=63/2
=32.5cmpower2
Answered by
0
9+x+x-7=22, side2=x=10cm, side3=x-7=3cm
by Heron's theoreme area=13.27cm²
by Heron's theoreme area=13.27cm²
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