Question

find the area of the triangle with the length of sides 9cm, 10cm and 17 cm​

Answer 1

Answer:

36cm^2

Step-by-step explanation:

according to heron's formula,

$\sqrt{s(s - a)(s - b)(s - c)}$

where, S=(A+B+C) /2

and, a, b, C are measures of sides of triangle,.

hence, as, A=9cm,B=10cm,C=17cm,

hence, S=(9+10+17)/2cm=36/2cm=18 cm

hence area=√18(18-9)(18-10)(18-17)

=√18 x 9 x 8 x 1

=√1296

=36cm^2

Answer 2

The answer to your question is 36 cm²

BY USING HERON'S FORMULA:

S=$\frac{a+b+c}{2}$

 =$\frac{9+10+17}{2}$

 = $\frac{36}{2}$

 = 18

area (triangle) = $\sqrt{S(S-a)(S-b)(S-c)}$

                        = $\sqrt{18(18-9)(18-10)(18-17)}$

                        = $\sqrt{18*9*8*1}$

                        = $\sqrt{2*9*9*2*4}$

                        = 9 * 2 * 2

                        = 36 cm²

Hope this helps

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