find the area of the triangle with the length of the sides 9 CM 10 cm and 17 cm
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Answer:
perimeter if the triangle is (9+10+17)cm=36cm
half of the perimeter is 36/2cm=18cm
so area of the triangle is
√18(18-9)(18-10)(18-17)sqcm
=√18.9.8.2sqcm
=18.2√2sqcm
=36√2sqcm
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