Question

find the area of the triangle with vertices (0,0),(6,0)and (0,5).

Answer 1

SOLUTION.......

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▪(0,0) = (x1,y1)
▪(6,0) = (x2,y2)
▪(0,5) = (x3,y3)

Now,
Area of triangle =
1/2 [ x1 (y2-y3)+x2 (y3-y1)+x3 (y1-y2) ]

= 1/2 [ 0 (0-5)+6 (5-0)+0 (0-0) ]
= 1/2 [ 0 + 30 + 0 ]
= 1/2 × 30
= 15 units ........ is the required area of given Triangle .

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↪ Hope this will help you ↩

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☛ ⛧⛧ Ⓜr. Thakur ⛧⛧

Answer 2

Answer:

The area of the triangle with vertices (0,0),(6,0)and (0,5) is 15 square unit.

Step-by-step explanation:

• Three vertices of the triangle are : A(0,0), B(6,0), C(0,5)
• For triangle Δ ABC , base is the distance between A and B on X-axis, i.e. 6.
• For triangle Δ ABC , height is the distance between A and C on         Y-axis, i.e. 5.
• Area of a triangle is = 1/2×(base×height) = 1/2×6×5 = 15 square unit.