find the area of the triangle with vertices A(0,4), B(0,0), C(3,0)
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1
Answer:
Take mate
Explanation:
Let ABC be a triangle having A(0,4);B(0,0);C(3,0)
Using distance formula, we get
AB=
(0−0)
2
+(0−4)
2
=
16
=4
BC=
(3−0)
2
+(0−0)
2
=
9
=3
CA=
(0−3)
2
+(4−0)
2
=
25
=5
Perimeter of △ABC=AB+BC+CA=4+3+5=12
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