Find the area of the triangle with vertices A(1,3) , b(-1,0), c(4,0)
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Answer:
8 sq unit
Step-by-step explanation:
x1 =1, x2 = - 1, x3 = 4 & y1 = 3, y2 = 0, y3 = 0
Area of triangle = 1/2*{x1(y2-y3) + x2(y3-y1) +x3(y1-y2)}
=1/2* {1(0-0) - 1(0-3) + 4(3-0)}
= 1/2* (0 +3 +13)
= 1/2 *(16)
= 8 sq. Unit
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