Question

Find the area of the triangles whose side is a=8cm b=11cm c=13cm​

Answer 1

Answer:

s = a+b+c/2

s = 8+11+13/2

s= 32/2

s= 16

$area \: of \: triangle \\ \sqrt{16(16 - 8)(16 - 11)(16 - 13} \\ \sqrt{16 \times 8 \times 5 \times 3 } \\ \sqrt{ 4 \times 2 \times 2 \times 4 \times 2 \times 5 \times 3} \\ 2 \times 4 \sqrt{2 \times 5 \times 3} \\ 8 \sqrt{ {30cm}^{2} }$

Step-by-step explanation:

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Answer 2

Answer:

use the herons formula

Step-by-step explanation:

underroot s(s-a)(s-b)(s-c)