find the area of the trianglr whose sides are 13cm 9 cm 6cm
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Answered by
2
to find the area of a triangle having sides of different lengths, we use the hero's formula ie√s(s- a)(s-b)(s-c)
so for finding "s" we will add all the sides and will devide it by 2
13+9+6/2=14
now we will put the formula
√14(14-13)(14-9)(14-6)
√14×1×5×8
√560
√7×2×5×2×2×2
=4√35
I hope this will help you.
so for finding "s" we will add all the sides and will devide it by 2
13+9+6/2=14
now we will put the formula
√14(14-13)(14-9)(14-6)
√14×1×5×8
√560
√7×2×5×2×2×2
=4√35
I hope this will help you.
jayasuriyan:
thank u
Answered by
0
HELLO MY DEAR FRIEND
THE GIVEN SIDES OF A TRIANGLE = 13 CM, 6CM, AND 9CM.
THE AREA OF A TRIANGLE = 1/2 *BASE * HEIGHT.
HERE LETS TAKE THE BASE AS 13 CM
AND HEIGHT = 9CM.
= 1/2*BASE*HEIGHT
= 1/2*13 cm* 9cm
= 1/2*117cm
= 58.5 cm square.
I THINK MY ANSWER IS CORRECT.
I HOPE THIS WILL HELP'S U..............*-*
# ✌SWETHAPAVS ✌#
THE GIVEN SIDES OF A TRIANGLE = 13 CM, 6CM, AND 9CM.
THE AREA OF A TRIANGLE = 1/2 *BASE * HEIGHT.
HERE LETS TAKE THE BASE AS 13 CM
AND HEIGHT = 9CM.
= 1/2*BASE*HEIGHT
= 1/2*13 cm* 9cm
= 1/2*117cm
= 58.5 cm square.
I THINK MY ANSWER IS CORRECT.
I HOPE THIS WILL HELP'S U..............*-*
# ✌SWETHAPAVS ✌#
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