Question

find the area of the triangular field with the length of sides 360m 450 m and 450m​

Answer 1

Answer:

Area =74237.7m2

Step-by-step explanation:

Use heron s formulae

s=a+b+c\2

s= 360+450+450/2

s=630

Area=√s(s-a)(s-b)(s-c)

Area=√630×(630-360)(630-450)(630-450)

Area= √630×270×180×180

Area=180√630×270

Area= 180×412.43

Area= 74237.7

Answer 2

$\bf\huge{\underline\pink{Question:-}}$

Find the area of the triangular field with length of sides 360m , 450m ,and 450m.

$\bf\huge{\underline\pink{Answer:-}}$

$\purple{★}$a = 360 m.

$\purple{★}$b = 450 m.

$\purple{★}$c = 450 m.

${⟹}$ $\large\bold{s = \frac{a + b + c}{2} }$

${⟹}$$\large\bold{s = \frac{360 + 450 + 450}{2} }$

${⟹}$ $\large\bold{s = \frac{1260}{2} = 630 }$

${⟹}$ $\bold{ Area \: of \: a \: triangle = \sqrt{s(s - a)(s - b)(s - c)} }$

${⟹}$ $\bold{ Area = \sqrt{630 \times (630 - 360)(630 - 450)(630 - 450)} }$

${⟹}$ $\bold{ Area = \sqrt{630 \times 270 \times 180 \times 180} }$

${⟹}$ $\bold{ Area = 16200 \sqrt{21m^{2} } }$